runtime fluent builder with gump.create() / gump.send(...)
England have beaten the Azzurri in all 32 meetings over the last 35 years but that record could slip in Rome on Saturday
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思路：单调递减栈，找「上一个比当前价格大的元素索引」。正序遍历，弹出所有 ≤ 当前价格的索引；跨度 = 当前索引 - 栈顶索引（栈空则为 当前索引 + 1）。
"People come into your office and say they're not having a very good day, or something's happened at home, and you have to try and see if you can support them. It's very varied."
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